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In mathematics, particularly in linear algebra and functional analysis, the polar decomposition of a matrix or linear operator is a factorization analogous to the polar form of a nonzero complex number ''z'' as where ''r'' is the absolute value of ''z'' (a positive real number), and is an element of the circle group. ==Matrix polar decomposition== The polar decomposition of a square complex matrix ''A'' is a matrix decomposition of the form : where ''U'' is a unitary matrix and ''P'' is a positive-semidefinite Hermitian matrix. Intuitively, the polar decomposition separates ''A'' into a component that stretches the space along a set of orthogonal axes, represented by ''P'', and a rotation (with possible reflection) represented by ''U''. The decomposition of the complex conjugate of is given by . This decomposition always exists; and so long as ''A'' is invertible, it is unique, with ''P'' positive-definite. Note that : gives the corresponding polar decomposition of the determinant of ''A'', since and . The matrix ''P'' is always unique, even if ''A'' is singular, and given by : where ''A'' * denotes the conjugate transpose of ''A''. This expression is meaningful since a positive-semidefinite Hermitian matrix has a unique positive-semidefinite square root. If ''A'' is invertible, then the matrix ''U'' is given by : In terms of the singular value decomposition of ''A'', ''A = W Σ V *'', one has : : confirming that ''P'' is positive-definite and ''U'' is unitary. Thus, the existence of the SVD is equivalent to the existence of polar decomposition. One can also decompose ''A'' in the form : Here ''U'' is the same as before and ''P''′ is given by : This is known as the left polar decomposition, whereas the previous decomposition is known as the right polar decomposition. Left polar decomposition is also known as reverse polar decomposition. The matrix ''A'' is normal if and only if ''P''′ = ''P''. Then ''UΣ = ΣU'', and it is possible to diagonalise ''U'' with a unitary similarity matrix ''S'' that commutes with ''Σ'', giving ''S U S *'' = ''Φ−1'', where ''Φ'' is a diagonal unitary matrix of phases ''eiφ''. Putting ''Q = V S *'', one can then re-write the polar decomposition as : so ''A'' then thus also has a spectral decomposition : with complex eigenvalues such that ''ΛΛ * = Σ2'' and a unitary matrix of complex eigenvectors ''Q''. 抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)』 ■ウィキペディアで「Polar decomposition」の詳細全文を読む スポンサード リンク
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